FAA General Practice Test

Question: 1 / 400

Calculate the total work input required to move a mobile hoist that raises a 350-pound engine 3 feet and moves it forward 12 feet using a constant force of 70 pounds.

420 foot-pounds

840 foot-pounds

To determine the total work input required for the mobile hoist, it is essential to understand that work is calculated using the equation \( \text{Work} = \text{Force} \times \text{Distance} \). In this scenario, there are two movements to evaluate: lifting the engine vertically and moving it horizontally.

First, calculate the work done to lift the engine. The force required to lift the engine is equal to its weight, which is 350 pounds, and it is raised to a height of 3 feet. Therefore, the work done in lifting the engine can be computed as follows:

\[

\text{Work}_{\text{lifting}} = \text{Force}_{\text{lifting}} \times \text{Distance}_{\text{lifting}} = 350 \, \text{pounds} \times 3 \, \text{feet} = 1050 \, \text{foot-pounds}.

\]

Next, calculate the work done to move the engine horizontally. The constant force used to move the engine forward is given as 70 pounds, and it is moved horizontally for a distance of 12 feet. Thus, the work done in this horizontal movement is:

\[

\

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1050 foot-pounds

1260 foot-pounds

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